10=39t-16t^2

Solution for 10=39t-16t^2 equation:

10=39t-16t^2

We move all terms to the left:

10-(39t-16t^2)=0

We get rid of parentheses

16t^2-39t+10=0

a = 16; b = -39; c = +10;
Δ = b2-4ac
Δ = -392-4·16·10
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{881}}{2*16}=\frac{39-\sqrt{881}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{881}}{2*16}=\frac{39+\sqrt{881}}{32}
$